You have two CSTRs and two PFRs each with a volume of $1\mathrm{.}6$m$^3.$ Use Figure $2$ to calculate the conversion for each of the reactors in the following

arrangements.

$($a$)$ Two CSTRs in series.

$($b$)$ Two PFRs in series.

$($c$)$ Two CSTRs in parallel with the feed. $F_{A0}$ divided equally between the two reactors.

$($d$)$ Two PFRs in parallel with the feed divided equally between the two reactors.

$($e$)$ A CSTR and a PFR in parallel with the flow equally divided. Atso calculate the overall conversion. $x.$

Xov FA$0-$ Facstr $-$ FAPFR FAO FAO FAO with FACSTR $=22$ XcSTR$.$ and Fapfr$=$ FA$0/2(1$ Xpfr$)$

$($f$)$ A PFR followed by a CSTR$.$

$($g$)$ A CSTR followed by a PFR$.$

$($h$)$ A PFR followed by two CSTRs$.$ Is this arrangement a good one or is there a better one?

You have two CSTRs and two PFRs each with a volume of $1\mathrm{.}6m^3.$ Use Figure $2-2$ to calculate the conversion for each of the reactors in the following arrangements.

$($a$)$ Two CSTRs in series.

$($b$)$ Two PFRs in series.

$($c$)$ Two CSTRs in parallel with the feed, $F_{AO},$ divided equally between the two reactors.

$($d$)$ Two PFRs in parallel with the feed divided equally between the two reactors.

$($e$)$ A CSTR and a PFR in parallel with the flow equally divided. Also calculate the overall conversion, $x_{ov}$

$x_{ov}=\frac{F_{A0}-F_{\text{A}\text{C}\text{S}\text{T}\text{R}}-F_{\text{A}\text{P}\text{F}\text{R}}}{F_{A0}},$ with $F_{\text{A}\text{C}\text{S}\text{T}\text{R}}=\frac{F_{A0}}{2}-\frac{F_{A0}}{2}{x}_{CSTR},$

$F_{\text{A}\text{P}\text{F}\text{R}}=\frac{F_{A0}(1-x_{PFR})}{2}$

$($f$)$ A PFR followed by a CSTR$.$

$($g$)$ A CSTR followed by a PFR$.$

$($h$)$ A PFR followed by two CSTRs$.$ Is this arrangement a good one or is there a better one?