Question: You may need to use the appropriate technology to answer this question. The calculations for a factorial experiment involving four levels of factor A, three

You may need to use the appropriate technology to answer this question. The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted in the following data; SST = 287, SSA = 28, SSB = 23, SSAB = 179, Set up the ANOVA table. (Round your values for mean squares and F to two decimal places, and your p-values to three decimal places.) Source Sum Degrees Mean p-value of Variation of Squares of Freedom Square Factor A Factor B Interaction Error Total Test for any significant main effects and any interaction effect. Use a = 0.05. Find the value of the test statistic for factor A. (Round your answer to two decimal places.) Find the p-value for factor A. (Round your answer to three decimal places.) p-value = State your conclusion about factor A. O Because the p-value s a = 0.05, factor A is not significant. O Because the p-value > a = 0.05, factor A Is significant Because the p-value s a = 0.05, factor A is significant. O Because the p-value > a = 0.05, factor A Is not significant. Find the value of the test statistic for factor B. (Round your answer to two decimal places.) Find the p-value for factor B. (Round your answer to three decimal places.) p-value = State your conclusion about factor B. O Because the puvalue s a = 0.05, factor B is not significant. O Because the p-value > a = 0.05, factor B is significant. O Because the p-value s a = 0.05, factor B is significant. Because the p-value > a = 0.05, factor B is not significant. Find the value of the test statistic for the Interaction between factors A and B. (Round your answer to two decimal places.) Find the p-value for the Interaction between factors A and B. (Round your answer to three decimal places.) p-value - State your conclusion about the Interaction between factors A and B. O Because the p-value > a = 0.05, the Interaction between factors A and B is significant. Because the p-value s a = 0.05, the interaction between factors A and B is not significant. Because the p-value s a = 0.DS, the interaction between factors A and B is significant. O Because the p-value >
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