Question: You should be able to answer this question after studying Unit 4. (a) A hyperbola in standard position has equation 9:102 4y? 100 = 0.

You should be able to answer this question after studying Unit 4. (a) A hyperbola in standard position has equation 9:102 4y? 100 = 0. (1) Find the vertices and asymptotes of the hyperbola. (ii) Sketch the hyperbola, labelling its vertices with their coordinates and its asymptotes with their equations. (iii) Find the eccentricity, foci and directrices of the hyperbola. (iv) Find a parametrisation of the part of this hyperbola that lies in the second quadrant (not including any points that lie on the :IJaxis or yaxis). Make sure to nd and include the restrictions that are needed on the values of the parameters. The equation 6:102 83:31; + 51:12 3:1,- 16y 20 = 0 represents a non-degenerate conic. (1) Determine the type of conic. (ii) Plot the conic using Maxima, and provide a screenshot of your plot, including the command that you used to produce the plot

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