You throw a baseball directly upward at time $t=0$ at an initial speed of $14\mathrm{.}9\frac{m}{s}.$

Ignore air resistance and use $g=9\mathrm{.}80\frac{m}{s^2}.$

Relative to the point where it leaves your hand, what is the maximum height $h_{\text{m}\text{a}\text{x}}$ reached by the ball?

$h_{\text{m}\text{a}\text{x}}=$

m

At what times $t_{\frac{1}{2},up}$ and $t_{\frac{1}{2},\text{d}\text{o}\text{w}\text{n}}$ does the ball pass through half the maximum height on the way up and the way down, respectively?

$t_{\frac{1}{2},up}=,s,t_{\frac{1}{2},\text{d}\text{o}\text{w}\text{n}}=$

s