You will be given multiple choices for each answer, one being $$None of the others$.$ You will choose the answer that matches yours or None if that is the case.

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Q$1.$ For the following program FOO, assuming each scoping method:

a$)$ Static and

b$)$ Dynamic Scoping,

show the output x at locations$******$ The program execution begins execution in MAIN.

PROGRAM FOO$()$

VAR$$ x : integer;$//$ this is global

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$//=========$ A $=============$

PROCEDURE A$()$

VAR$$ d : integer;

BEGIN

x :$=5$;

d :$=6$;

B$()$;$//$ call to B

writeln$($x$)$;$//$ output the value of x $***$

END $//$ procedure A

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$//=======$ B $=============$

PROCEDURE B$()$ BEGIN

writeln$($x$)$;$//$ output the value of x $**$

END $//$ procedure B

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$//=======$ MAIN $=====================$

PROCEDURE MAIN$()$

VAR$$ x : integer;

BEGIN$//($Program starts here

x :$=10$;

A$()$;$//$ call to A

writeln$($x$)$;$//$ output the value of x $*$

END

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END. $//$ program FOO

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a$)$ Static scoping?$$ X:$*5**5***10$

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b$)$ Dynamic scoping? X:$*5**5***5$

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Q$2.$ For the program in Q$1,$ assuming Dynamic Scoping, what would be the referencing environment for statements when executing the first line $($so after the BEGIN$)$ in

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a$)$ procedure A$?($include only variable names$)$

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b$)$ procedure B$?($include only variable names$)$

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c$)$ procedure MAIN? $($include only variable names$)$

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Q$3.$ True or False

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a$)$ The declaration of a local variable with the same name as a non$-$local variable can only hide the non$-$local variable in the local scope when using Static Scoping but not when using Dynamic Scoping.

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b$)$ A globally declared variable will always be visible everywhere in a program.

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c$)$ Run$-$time overhead is the main reason Dynamic scoping is not chosen over Static scoping.

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d$)$ The type and value are always bound to a variable name at the same time.

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e$)$ A Heap$-$Dynamic variable typically requires the user to create a Reference or Pointer typed variable to allow them to be accessed by the user.