For the power system shown on the bottom left, the synchronous motor absorbs 1500 MW at...

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For the power system shown on the bottom left, the synchronous motor absorbs 1500 MW at 0.8 power factor leading with the bus 3 voltage at 18 kV. Equipment ratings are ... Generator 1: Generator 2: 1000 MVA, 18 kV, X" = 0.2 per unit 1000 MVA, 18 kV, X" = 0.2 pu Synchronous motor 3: 1500 MVA, 20 kV, X"= 0.2 pu Three-phase A-Y transformers T₁, T₂, T3, T4: 1000 MVA, 500 kV Y/20 kV A, X = 0.1 pu 1500 MVA, 500 kV Y/20 kV Y, X = 0.1 pu Three-phase Y-Y transformer T5: Neglecting resistance, transformer phase shift, and magnetizing reactance AND using a base of 100 MVA and 500 kV for the 50-ohm line, we drew the equivalent per-unit circuit diagram on the lower right. Determine the bus 1 and bus 2 voltages in kV. Assume that generators 1 and 2 deliver equal real powers and equal reactive powers. Also assume a balanced three-phase system with positive-sequence sources. The per-unit equivalent circuit is shown on the right. YO 1 J 08 T₁ T3 J 10380 25 (2 Y 3 150 Ω PHOTO j2 (2 XX 2. HBCĐ 10380 T₂ TA 2 2 j0.0162 + V₁ jo.01 ree (3) j0.02 ле j0.0133 jo.01 jo.01 j0.0008 j0.01 reeree eerle 1/2 T₂ j0.0067 j0.01 + سقف j0.0162 82 For the power system shown on the bottom left, the synchronous motor absorbs 1500 MW at 0.8 power factor leading with the bus 3 voltage at 18 kV. Equipment ratings are ... Generator 1: Generator 2: 1000 MVA, 18 kV, X" = 0.2 per unit 1000 MVA, 18 kV, X" = 0.2 pu Synchronous motor 3: 1500 MVA, 20 kV, X"= 0.2 pu Three-phase A-Y transformers T₁, T₂, T3, T4: 1000 MVA, 500 kV Y/20 kV A, X = 0.1 pu 1500 MVA, 500 kV Y/20 kV Y, X = 0.1 pu Three-phase Y-Y transformer T5: Neglecting resistance, transformer phase shift, and magnetizing reactance AND using a base of 100 MVA and 500 kV for the 50-ohm line, we drew the equivalent per-unit circuit diagram on the lower right. Determine the bus 1 and bus 2 voltages in kV. Assume that generators 1 and 2 deliver equal real powers and equal reactive powers. Also assume a balanced three-phase system with positive-sequence sources. The per-unit equivalent circuit is shown on the right. YO 1 J 08 T₁ T3 J 10380 25 (2 Y 3 150 Ω PHOTO j2 (2 XX 2. HBCĐ 10380 T₂ TA 2 2 j0.0162 + V₁ jo.01 ree (3) j0.02 ле j0.0133 jo.01 jo.01 j0.0008 j0.01 reeree eerle 1/2 T₂ j0.0067 j0.01 + سقف j0.0162 82

Answer rating: 100% (QA)

The given problem requires us to determine the bus 1 and bus 2 voltages in kilovolts kV by analyzing the perunit equivalent circuit diagram of a power system To solve for the voltages at bus 1 V1 and ... View the full answer