Your answer is partially correct.

A golf ball strikes a hard, smooth floor at an angle of $\backslash (33\mathrm{.}2^\{\backslash$circ$\}\backslash )$ and, as the drawing shows, rebounds at the same angle. The mass of the ball is $0\mathrm{.}0438$ kg $,$ and its speed is $\backslash (43\mathrm{.}7\backslash$mathrm$\{$~m$\}/\backslash$mathrm$\{$s$\}\backslash )$ just before and after striking the floor. What is the magnitude of the impulse applied to the golf ball by the floor? $($Hint: Note that only the vertical component of the ball's momentum changes during impact with the floor, and ignore the weight of the ball.$)$