Your answer is partially correct.

Water flows at a rate of $2\mathrm{.}0f\frac{t^3}{s}$ in an old, rusty $5\mathrm{.}2-$in$.-$diameter pipe that has a relative roughness of $0\mathrm{.}010.$ It is proposed that by inserting a smooth plastic liner with an inside diameter of $4\mathrm{.}6$ in$.$ into the old pipe as shown in the Figure the pressure drop per mile can be reduced. Is it true that the lined pipe can carry the required $2\mathrm{.}0f\frac{t^3}{s}$ at a lower pressure drop than in the old pipe?

Support your answer with appropriate calculations.

Pressure drop is a function of flow rate and roughness.

What is the mean velocity for the current $5\mathrm{.}2$ in$.$ diameter pipe?

$V_0=,f\frac{t}{s}$

What is the Reynolds number for the current $5\mathrm{.}2$ in diameter pipe?

$Re=$

What is the friction factor for the current $5\mathrm{.}2$ in diameter pipe?

$f_0=$

What is the pressure drop per mile for the current $5\mathrm{.}2$ in diameter pipe?

$p_o=,\frac{}{m}$ile

eTextbook and Media

Attempts: $6$ of $7$ used

Part $2$

Pressure drop is a function of flow rate and roughness.

What is the mean velocity for the new $4\mathrm{.}6$ in$.$ diameter pipe?

$V_o=,f\frac{t}{s}$

What is the Reynolds number for the new $4\mathrm{.}6$ in diameter pipe?

$Re=$

What is the friction factor for the new $4\mathrm{.}6$ in diameter pipe?

$f_0=$

What is the pressure drop per mile for the new $4\mathrm{.}6$ in diameter pipe?

$p_0=$ psi$/$mile

Is it true that the lined pipe can carry the required flow rate at a lower pressure drop than in the old pipe?

eTextbook and Media