Question: Your task is to design a circuit that accepts a 3-bit binary number as input, converts it to its equivalent 0- 9 octal value, then
Your task is to design a circuit that accepts a 3-bit binary number as input, converts it to its equivalent 0- 9 octal value, then displays the octal value on a seven-segment display by outputting 0/1 on the correct pins A-G of the seven-segment display. Your circuit accepts the binary inputs X, Y, and Z, which, taken together, equate to the octal digits 0-9 shown in the table below:
| digits | x | y |
| 0 | 0 | 0 |
| 1 | 0 | 1 |
| 2 | 1 | 0 |
| 3 | 1 | 1 |
| 4 | 0 | 0 |
| 5 | 0 | 1 |
| 6 | 1 | 0 |
| 7 | 1 | 1 |
The outputs of your circuit are connected to and turn on the appropriate segments A-G as shown in Fig. 1 and Fig. 2 above. The following Logisim screen shot shows a circuit (minus the details) that displays the digit 1. Your circuit will have additional inputs to display the digits 0 and 2 through 7. Please note that you need only provide the circuit for one digit, not two or three. For example, the three digits of the octal number equivalent to a 9-bit binary number may be displayed sequentially, not simultaneously.
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
