Y(S)=((12)/(S(S+2)^(2)+1))

Then, Final value

=

\ \\\\table[[A,Zero,B,

(12)/(5)

,C,

\\\\infty

,D,None of them]]\

{

(

:Y(t)=(7l^(-4t)-4l^(-4t)])

}, Then Initial value

=

\ \\\\table[[A,

3e^(-4t)

,B,3,C,

-3e^(-4t)

,D,None of them]]\ 13- The response of first-order system reaches to

63%

of its final value during:\ \\\\table[[A,Peak Time,B,Time constant,C,Settling Time,D,None of them]]

Y(S)=(12/[S(S+2)2+1]) Then, Final value = 12- Y(t)=(74t44t]), Then Initial value = 13- The response of first-order system reaches to 63% of its final value during