Question: z - j z + j (a) Let D = {ze C|Imz > 0} and f: D C, f (z) = Show that the

z - j z + j (a) Let D = {ze C|Imz > 0} and f: D C, f (z) = Show that the function f maps D conformally to the open disc D2 {z C| | z| < 1} . = (b) Prove that f(z). = e maps the lines x = a, y = a into orthogonal curves. Does f (z) = z have the same property?

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