A 3.00-g bullet (c = 0.030 5 cal/gC = 128 J/kgC) moving at 180 m/s enters a

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A 3.00-g bullet (c = 0.030 5 cal/g·°C = 128 J/kg·°C) moving at 180 m/s enters a bag of sand and stops. By what amount does the temperature of the bullet change if all its KE becomes thermal energy that is added to the bullet?

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Schaums Outline Of College Physics

ISBN: 9781259587399

12th Edition

Authors: Eugene Hecht

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Question Posted: Oct 31, 2023 02:48 PM

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A 3.00-g bullet (c = 0.030 5 cal/gC = 128 J/kgC) moving at 180 m/s enters a

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The bullet loses KE in the amount KE mv 300 10 kg180 ms 4...View the full answer

Schaums Outline Of College Physics

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