In the Bohr theory the total energy of the orbiting electron, E n , equals the sum

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In the Bohr theory the total energy of the orbiting electron, En, equals the sum of the electron’s KE plus its PE, where from Coulomb’s Law, PE = -k0e2/rn. Show thatEn = -koe/2rn n 1, 2, 3, ... = (43.13)

The minus sign arises because this is a bound state and the PE is negative.

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