The 40-loop coil shown in Fig. 30-12 carries a current of 2.0 A in a magnetic field
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The 40-loop coil shown in Fig. 30-12 carries a current of 2.0 A in a magnetic field B = 0.25 T. Find the torque on it. How will it rotate?
Transcribed Image Text:
N B=0.25 T a 12 cm 10 cm. b C Fig. 30-12 12 A S
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Method 1 The coil is composed of 40 turns of wire Therefore N 40 and T NIAB ...View the full answer
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