When n = 1 in Eq. (43.9), we get the radius of the lowest energy orbit (the
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When n = 1 in Eq. (43.9), we get the radius of the lowest energy orbit (the ground state orbit) called the Bohr radius. Numerically that’s.
Using Eq. (43.9), show that the diameter of a hydrogen atom is just about 0.10 nm, thereby confirming Eq. (43.10) to four significant figures.
Transcribed Image Text:
r₁ = 0.0529177 nm (43.10)
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