Question: Show for the binomial distribution that B(k; n, 0) = B(n- k;n, 0) only if the distribution is symmetric-B(k; n,0) is the probability of getting
Show for the binomial distribution that B(k; n, 0) = B(n- k;n, 0) only if the distribution is symmetric-B(k; n,0) is the probability of getting up to k "successes"
in n random dichotomous trials each of which has the probability of success, and B(k; n, 0) is the probability of getting k or more successes in those n trials.
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