For four means, a multiple comparison method provides 95% confidence intervals for the differences between the six pairs. Then

(a) For each confidence interval, there is a 0.95 chance that it contains the population difference.

(b) P(all six confidence intervals are correct) = 0.70.

(c) P(all six confidence intervals are correct) = 0.95.

(d) P(all six confidence intervals are correct) = (0.95)6.

(e) P(at least one confidence interval does not contain the true difference) = 0.05.

(f) The confidence intervals are wider than separate 95%
confidence intervals for each difference.