Question: Let (mathbf{X}) be an (n)-dimensional normal random vector with mean vector (boldsymbol{mu}) and covariance matrix (boldsymbol{Sigma}), where the determinant of (boldsymbol{Sigma}) is non-zero. Show that
Let \(\mathbf{X}\) be an \(n\)-dimensional normal random vector with mean vector \(\boldsymbol{\mu}\) and covariance matrix \(\boldsymbol{\Sigma}\), where the determinant of \(\boldsymbol{\Sigma}\) is non-zero. Show that \(\boldsymbol{X}\) has joint probability density
\[ f_{X}(x)=\frac{1}{\sqrt{(2 \pi)^{n}|\Sigma|}} \mathrm{e}^{-\frac{1}{2}(x-\mu)^{\top} \Sigma^{-1}(x-\mu)}, \quad x \in \mathbb{R}^{n} \]
Step by Step Solution
3.47 Rating (150 Votes )
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
