Let X be a random variable with mean and let E[(X ) 2k ] exist.
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Let X be a random variable with mean μ and let E[(X − μ)2k] exist. Show, with d > 0, that P(|X − μ| ≥ d) ≤ E[(X − μ)2k]/d2k. This is essentially Chebyshev’s inequality when k = 1. The fact that this holds for all k = 1, 2, 3, . . . , when those (2k)th moments exist, usually provides a much smaller upper bound for P(|X − μ| ≥ d) than does Chebyshev’s result.
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Proof of Show with d 0 that PX d EX 2kd2k Let EX and let a denote the leading coefficient of Xk Sinc...View the full answer
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Related Book For
Introduction To Mathematical Statistics
ISBN: 9780321794710
7th Edition
Authors: Robert V., Joseph W. McKean, Allen T. Craig
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