A company sent its employees to attend two different English courses. The company is interested in knowing if there is any difference between the two courses attended by its employees. When the employees returned from the courses, the company asked them to take a common test. The summary statistics of the test results of each of the two English courses are recorded in the following table:

a. Identify the parameter(s) that would help the company determine the difference between the two courses.

b. State the appropriate null and alternative hypotheses that the company would like to test.

c. After conducting the hypothesis test at the 5% significance level, the company found the p-value = .327. Interpret this result for the company.

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Course 1 n₁ = 50 x₁ = 75.1 X1 $1 12.8 = Course 2 n₂ = 50 X2 72.1 $2 14.6 -= =