Question: Show that if the random variable X has probability density function then X 2l v 2 has a chi-square distribution with 3 degrees of freedom.

Show that if the random variable X has probability density function

fx(x) == exp(- x>0, >0 20 0, otherwise,

then X 2l v 2 has a chi-square distribution with 3 degrees of freedom.

fx(x) == exp(- x>0, >0 20 0, otherwise,

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