The 90th percentile of (mathrm{NO}_{2}) is 44.93. Can you conclude that people whose exposure to (mathrm{NO}_{2}) is
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The 90th percentile of \(\mathrm{NO}_{2}\) is 44.93. Can you conclude that people whose exposure to \(\mathrm{NO}_{2}\) is in the top \(10 \%\) have lower mean FEV1 than those in the lower \(90 \%\)?
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