Question: =+d. Suppose that the diameter distribution is normal. Then the 90th percentile of the diameter distribution is m 1 1.28s (so 90% of all trees

=+d. Suppose that the diameter distribution is normal. Then the 90th percentile of the diameter distribution is m 1 1.28s (so 90% of all trees have diameters less than this value). Compute a point estimate for this percentile. (Hint:

First compute an estimate of m in this case; then use it along with your estimate of s from Part (a).)

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