Reaction of the compound corresponding to spectrum E with SOCl₂ produces a chloroalkane, C₄H₇Cl, whose NMR spectrum is almost identical with spectrum E, except that the broad signal at δ = 1.5 ppm is absent. Its IR spectrum shows bands at 700, 925, 985, 1640, and 3090 cm^-1. Treatment with H₂ over PtO₂ results in C₄H₉Cl. Its IR spectrum reveals the absence of all the bands quoted for its precursor, except for the signal at 700 cm^-1. Identify these two molecules.

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1Η ΝMR 3 H 6.00 5.95 5.90 5.85 5.80 1 H1H 1 H 1 H 1 H (CH3)4Si 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 0.5 0.0 300-MHz 'H NMR spectrum ppm (8) E