Find the focal length and the positions of the focal points and principle points of a single thick lens shown in the following figure. The index of the lens is 1.5 , its axial thickness \(25 \mathrm{~mm}\), the radius of the first surface \(22 \mathrm{~mm}\), and that of the second surface \(16 \mathrm{~mm}\). The equation for the focal length for a thick lens is given by

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f = s $2 not Eq. (3.46); the former reduces to the latter in limit of a thin lens. F I < < $1=00 A B H E G H' F' -1 2