Question: 1. gcd recursion theorem Prove the god recursion theorem: For any a NU {0} and be N, we have gcd (a, b) = gcd

1. gcd recursion theorem Prove the god recursion theorem: For any a ∈ NU {0} and be N, we have gcd

(a,

b) = gcd

(b, a mod b).

(2.25)

(Hint: Show that both expressions are divisors of each other. Why does this guaran-

tee their equality?)

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