Question: Given the system in state equation form, [frac{d mathbf{x}(t)}{d t}=mathbf{A} mathbf{x}(t)+mathbf{B} u(t)] where (a) (mathbf{A}=left[begin{array}{ccc}1 & 0 & 0 0 & -3 & 0
Given the system in state equation form,
\[\frac{d \mathbf{x}(t)}{d t}=\mathbf{A} \mathbf{x}(t)+\mathbf{B} u(t)\]
where
(a) \(\mathbf{A}=\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & -3 & 0 \\ 0 & 0 & -2\end{array}ight]\)
\(\mathbf{B}=\left[\begin{array}{l}1 \\ 0 \\ 1\end{array}ight]\)
(b) \(\mathbf{A}=\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & -2 & 0 \\ 0 & 0 & 3\end{array}ight]\)
\(\mathbf{B}=\left[\begin{array}{l}0 \\ 1 \\ 1\end{array}ight]\)
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