Does (r^{prime}=e^{-frac{1}{4}} r=0.788 r), which comes in calculation of inductance, play a role in capacitance computations? (a)
Question:
Does \(r^{\prime}=e^{-\frac{1}{4}} r=0.788 r\), which comes in calculation of inductance, play a role in capacitance computations?
(a) Yes
(b) No
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Power System Analysis And Design
ISBN: 9781305632134
6th Edition
Authors: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Question Posted: