Does (r^{prime}=e^{-frac{1}{4}} r=0.788 r), which comes in calculation of inductance, play a role in capacitance computations? (a)

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Does \(r^{\prime}=e^{-\frac{1}{4}} r=0.788 r\), which comes in calculation of inductance, play a role in capacitance computations?

(a) Yes

(b) No

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Power System Analysis And Design

ISBN: 9781305632134

6th Edition

Authors: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

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