Repeat Problem 6-9 when the voltage across a 20-mH inductor is \(v_{\mathrm{L}}(t)=100 e^{-2500 t} \mathrm{~V}\). Plot \(i_{\mathrm{L}}(t)\) versus time when \(i_{\mathrm{L}}(\mathrm{o})=+1 \mathrm{~A}\).

Data From Exercise 6-9

For \(t \geq 0\), the voltage across a \(220-\mathrm{mH}\) inductor is \(v_{\mathrm{L}}(t)=25 e^{-200 t} \mathrm{~V}\). Plot \(i_{\mathrm{L}}(t)\) versus time when \(i_{\mathrm{L}}(\mathrm{o})=100\) \(\mathrm{mA}\).

(a) Solve using Multisim. In Multisim, use the exponential voltage source, and set its initial value to \(25 \mathrm{~V}\) and the pulsed value to o V. Set the rise-time appropriately. Set the fall delay time well beyond the period over which you want to observe the response. Then, click on the inductor and set the inductor's initial condition to \(100 \mathrm{~mA}\). Plot the output using the transient analysis. Under "Analysis parameters," be sure to check the box under initial conditions to "Userdefined" and set the "End time" to display at least five time constants.

(b) Solve and graph using MATLAB.