Question: Approximating the inter atomic potential as a harmonic oscillator with angular frequency vib , the vibrational - rotational energy levels of a diatomic molecule
Approximating the inter atomic potential as a harmonic oscillator with angular frequency ωvib, the vibrational - rotational energy levels of a diatomic molecule are given by E(n, J) = ℏωvib(n+1/2)+ℏ2 J(J+1)/(2μr2e ). Here re is the equilibrium inter atomic separation,μ is the reduced mass, and J = 0, 1, 2, . . . is the rotational quantum number. The CO bond in carbon monoxide has re ≅ 1.13 × 10−10 m and ℏωvib =0.2657 eV. Ignoring rotations, what is the wavelength λvib (in microns) of the radiation absorbed when the CO molecule makes a transition from vibrational level n to n + 1? Vibrational transitions are always accompanied by a transition from rotational level J to J ±1. There sult is a sequence of equally spaced absorption lines centered at λvib. What is the spacing between these vibrational-rotational absorption lines?
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