Question: Using the data given in Table 12.1, estimate the enthalpy added to one kilogram of water that undergoes the following transformations: (a) From 0

Using the data given in Table 12.1, estimate the enthalpy added to one kilogram of water that undergoes the following transformations: 

(a) From 0 C to 90 C at p = 105 Pa; 

(b) From 95 C to 105 C at p = 105 Pa; 

(c) From 95 C to 105 C at p = 1.2 × 105 Pa. 


Table 12.1

p(Tsat) 1x 10° Pa (99.61°C) 1.2 x 10° Pa (104.78 °C) h Temp [°C] [m*kg] [m*/kg] [kJ/kg] [kJ/kg] [kJ/kg K] [kJ/kg] [k/kg] [kJ/kg K] Sat. Lig. 1.0432 x 10 3 Evap. Sat. Vap. 3. 439.23 1.0473 x 10 1.4274 439.36 2243.7 2683.1 1.3609 5.9368 417.40 417.40 1.3028 1.6929 6.0560 2088.2 

p(Tsat) 1x 10 Pa (99.61C) 1.2 x 10 Pa (104.78 C) h Temp [C] [m*kg] [m*/kg] [kJ/kg] [kJ/kg] [kJ/kg K] [kJ/kg] [k/kg] [kJ/kg K] Sat. Lig. 1.0432 x 10 3 Evap. Sat. Vap. 3. 439.23 1.0473 x 10 1.4274 439.36 2243.7 2683.1 1.3609 5.9368 417.40 417.40 1.3028 1.6929 6.0560 2088.2 2505.6 2257.4 2674.9 2072.5 1.6939 7.3588 1.4284 2511.7 7.2977 1.0002 x 10-3 -0.0404 0.0597 -0.0001 1.0001 x 10-3 -0.0400 0.0800 -0.0001 1.0003 x 10-3 42.017 1.0018 x 10-3 1.0044 x 10-3 1.0078 x 10-3 L.0121 x 10-3 1.0171 x 10-3 1.0227 x 10 3 1.0290 x 10-3 1.0359 x 10-3 376.95 377.08 0.00 1.0003 x 10-3 1.0018 x 10-3 1.0044 x 10-3 1.0078 x 10-3 1.0121 x 10-3 1.0171 x 10-3 10 42.018 42.118 0.1511 42.137 0.1511 20 83.906 84.006 0.2965 83.905 84.025 0.2965 30 125.72 125.82 04367 125.72 125.84 0.4367 40 167.51 167.62 05724 167.51 167.63 0.5724 50 209.32 209.42 0.7038 209.31 209.43 0.7038 60 251.15 251.25 0.8313 251.15 251.26 0.8312 1.0227 x 10-3 1.0290 x 10-3 1.0359 x 10-3 376.96 70 293.02 293.12 0.9551 293.02 293.14 0.9551 80 334.94 335.05 1.0755 334.95 335.07 1.0755 90 377.06 1.1928 1.1928 1.6959 1.7932 1.0435x 10-3 1.4906 2506.2 2675.8 2716.6 7.3610 7.4678 419.05 2535.7 419.18 2714.6 100 1.3072 7.3794 120 2537.3 140 2567.8 2756.7 7.5672 2566.5 1.8891 1.9841 1.5712 2755.1 7.4800 160 2796.4 7.6610 1.6508 2598.0 2628.1 2658.2 2688.4 2597.0 2627.3 2657.5 1.8867 2687.8 2914.2 2795.1 7.5745 7.6643 180 2.0785 2836.0 7.7503 1.7299 2834.9 2.1724 2.2661 7.8356 7.9174 200 2875.5 1.8085 2874.5 7.7499 220 2915.0 7.8320

Step by Step Solution

3.48 Rating (158 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a From the table the enthalpy per kilogram at 90 C is 37706 kJ and at 0 C is 006 kJ so H377 kJ ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related The Physics Energy Questions!