Verify the statements made after eq. (18.2)

About the energy released for the case of thermal-neutron induced fission of ²³⁵U. First, use measured mass excesses to show that the asymmetric fission reaction n_th + ²³⁵U ? ⁹²Kr + ¹⁴⁴Ba has a smaller Q-value than the symmetric fission into two ¹¹⁸Pd nuclei. Next show that the reaction n_th + ²³⁵U ? 2(¹¹⁶Pd) + 4n also has a smaller Q-value than the symmetric fission into two ¹¹⁸Pd nuclei. Finally, show that the SEMF under estimates the binding energy of ¹¹⁸Pd and therefore over estimates the Q-value for the symmetric fission into two ¹¹⁸Pd nuclei.

Transcribed Image Text:

Qfission 2B(Zmin (A)/2, A/2) – B(Zmin(A), A)