His body is again leaning back at 30.0^oto the vertical, but now the height at which the rope is held above but still parallel to the ground is varied. The tension in the rope in front of the competitor (T₁) is measured as a function of the shortest distance between the rope and the ground (the holding height). Tension T₁is found to decrease as the holding height increases. What could explain this observation? As the holding height increases,

(a) The moment arm of the rope about his feet decreases due to the angle that his body makes with the vertical;

(b) The moment arm of the weight about his feet decreases due to the angle that his body makes with the vertical;

(c) A smaller tension in the rope is needed to produce a torque sufficient to balance the torque of the weight about his feet;

(d) His center of mass moves down to compensate, so less tension in the rope is required to maintain equilibrium.

In a study of the biomechanics of the tug-of-war, a 2.0-m-tall, 80.0-kg competitor in the middle of the line is considered to be a rigid body leaning back at an angle of 30.0^o to the vertical. The competitor is pulling on a rope that is held horizontal a distance of 1.5 m from his feet (as measured along the line of the body). At the moment shown in the figure, the man is stationary and the tension in the rope in front of him is T₁ = 1160 N. Since there is friction between the rope and his hands, the tension in the rope behind him, T₂, is not equal to T₁. His center of mass is halfway between his feet and the top of his head. The coefficient of static friction between his feet and the ground is 0.65.

Transcribed Image Text:

Side view. T2 1.5m 30°