Question: Suppose a binomial queue of N = 2k 1 elements is built. Alternately perform M insert and deleteMin pairs. Clearly, each operation takes O(logN)

Suppose a binomial queue of N = 2k − 1 elements is built. Alternately perform M insert and deleteMin pairs. Clearly, each operation takes O(logN) time. Why does this not contradict the amortized bound of O(1) for insertion?

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