Question: Suppose that each mutant gene in Exercise 23 has a 1.0% chance of mutating back to the original type each cell division. Use the Markov

Suppose that each mutant gene in Exercise 23 has a 1.0% chance of mutating back to the original type each cell division. Use the Markov chain approach to find the fraction of mutant genes after 15 cell divisions. How much difference does the correction mechanism make?

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