Suppose that Show that fa{x) is continuous at x = 0 when a > 0 and differentiable
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Show that fa{x) is continuous at x = 0 when a > 0 and differentiable at x = 0 when a > 1. Graph these functions for a = 1 and a = 2 and give a geometric interpretation of your results.
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fax" sin x=0.
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Clearly f x x If 0 then x 0 as x 0 Thus by the Squeeze Theorem f x 0 f0 as x 0 ...View the full answer
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