Question: Suppose the events B1, B2, and B3 are mutually exclusive and complementary events, such that P(B1) = .2, P(B2) = .15, and P(B3) = .65.

Suppose the events B1, B2, and B3 are mutually exclusive and complementary events, such that P(B1) = .2, P(B2) = .15, and P(B3) = .65. Consider another event A such that P(A) = .4. If A is independent of B1, B2, and B3, use Bayes's Rule to show that P(B1|A) = P(B1) = .2.

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