Question: Ten treatments were compared for their effect on the liver in mice.There were 13 animals in each treatment group. The ANOVA gave MS(within) = 0.5842.

Ten treatments were compared for their effect on the liver in mice.There were 13 animals in each treatment group. The ANOVA gave MS(within) = 0.5842. The mean liver weights are given in the table.37

Ten treatments were compared for their effect on the liver

(a) Use Fisher LSD intervals to compare all pairs of means with aCW. = 0.05 and summarize the results in a table similar to Table 11.9.4. [First note that the sample sizes are equal; hence the same margin of error (t × SEDn) can be used for all comparisons. Furthermore, since a summary table is desired, the actual intervals need not be computed: Simply check if |dab| > t × SEDab. If it is, then the computed interval would not contain zero, so the difference is significant. Finally, not all possible comparisons (there are 45) need to be checked: when using the method of underlining to summarize results, once a subarray of groups has been underlined all comparisons within the subarray are considered nonsignificant.]
(b) If Bonferroni's method is used with aew = 0.05 instead of Fisher's LSD in part (a), are any pairs of means significantly different?

Mean liver Treatment weight (gm) Treatment weight (gm) Mean liver 2.59 2.28 2.34 2.07 2.40 2.84 2.29 2.45 2.76 2.37 10

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a For these data s pooled 05842 07643 SE Dab 07643 113 113 02998 and using Table 4 with df 100 120 1... View full answer

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