The 1H NMR spectrum of a compound, C4H9Br, consists of a single sharp peak. What is its

Question:

The 1H NMR spectrum of a compound, C4H9Br, consists of a single sharp peak. What is its structure? The spectrum of an isomer of this compound consists of a doublet at δ 3.2, a complex pattern at δ 1.9, and a doublet at δ 0.9, with relative areas 2 : 1 : 6. What is its structure?
Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Organic Chemistry A Short Course

ISBN: 978-1111425562

13th edition

Authors: Harold Hart, Christopher M. Hadad, Leslie E. Craine, David J. Hart

Question Posted: