The base of a solid is bounded by one arch of y = cos x, -/2

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The base of a solid is bounded by one arch of y = √cos x, -π/2 ≤ x ≤ π/2, and the x-axis. Each cross section perpendicular to the x-axis is a square sitting on this base. Find the volume of the solid.

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Calculus

ISBN: 978-0131429246

9th edition

Authors: Dale Varberg, Edwin J. Purcell, Steven E. Rigdon

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Question Posted: Jun 21, 2016 10:06 AM

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The base of a solid is bounded by one arch of y = cos x, -/2

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