Question: The boundary-value problem Y = y' + 2y + cos x, 0 x /2, y(0) = 0.3, y (/2) = 0.1

The boundary-value problem
Y" = y' + 2y + cos x, 0 ≤ x ≤ π/2, y(0) = −0.3, y (π/2) = −0.1

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