The de Broglie wavelength, A, of a 5.00-MeV alpha particle is 6.40 fm, and the closest distance,

Question:

The de Broglie wavelength, A, of a 5.00-MeV alpha particle is 6.40 fm, and the closest distance, rmin, to the gold nucleus this alpha particle can get is 45.5 fm (calculated in Example 39.1). How does the ratio rmim/λ vary with the kinetic energy of the alpha particle?