Question: The figure on the left below shows a small light bulb suspended at distance d1 = 250 cm above the surface of the water in
The figure on the left below shows a small light bulb suspended at distance d1 = 250 cm above the surface of the water in a swimming pool where the water depth is d2 = 200 cm. The bottom of the pool is a large mirror. How far below the mirror's surface is the image of the bulb? (Hint: Construct a diagram of two rays like that of the figure on the right, but take into account the bending of light rays by refraction. Assume that the rays are close to a vertical axis through the bulb, and use the small-angle approximation in which sin (?)= tan(?)=?)
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Figure 2 shows the refracted and reflected rays Applying the law of refraction yields 1 where ... View full answer
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