The half-life of 27Mg is 9.50 min. (a) Initially there were 4.20 1012 27Mg nuclei present.
Question:
(a) Initially there were 4.20 × 1012 27Mg nuclei present. How many 27Mg nuclei are left 30.0 min later?
(b) Calculate the 27Mg activities (in Ci) at t = 0 and t = 30.0 min.
(c) What is the probability that any one 27Mg nucleus decays during a 1-s interval? What assumption is made in this calculation?
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Step by Step Answer:
a First we calculate the rate constant using Equation 136 of the text Next we use Equation 133 of ...View the full answer
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