Question: The Levinson-Durbin algorithm described in section 11.3.1 solved the linear equations ? m a m? = ? ? m where the right-hand side of this

The Levinson-Durbin algorithm described in section 11.3.1 solved the linear equations

?mam?= ? ?m

where the right-hand side of this equation has elements of the autocorrelation sequence that are also elements of the matrix ?. Let us consider the more general problem of solving the linear equations

?mbm = cm

where cm is an arbitrary vector. (The vector bm is not related to the coefficients of the backward predictor.) Show that the solution to ?mbm = cm?can be obtained from a generalized Levinson-Durbin algorithm which is given recursively as

bm(m) = c(m) - ?bIm ? 1bm ? 1/Efm ? 1

bm(k) = bm ? 1(k) ? bm(m)avm ? 1(m ? k)?k = 1, 2, . . . ., m ? 1

? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?? m = 1, 2. . . p ?

Where bI(1) = c(1)/?xx(0) = c(1)/Ef0?and am(k) is given by (11.3.17). Thus a second recursion is required to solve the equation ?mbm = cm.

| = 1, 2. .... p La, (k)Yz:{l -- k) = 0

| = 1, 2. .... p La, (k)Yz:{l -- k) = 0 (11.3.1) ap(0) = 1 am (k) = am-i(k) + Kma-1 (m - k) k = 1, 2,...., m - k) = Um-1 (k) + am (m)a-1(m - (11.3.17) m = 1.2,....p

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