Question: The mercury in a 1.0451-g sample was precipitated with an excess of paraperiodic acid, H5IO6: The precipitate was filtered, washed free of precipitating agent, dried,

The mercury in a 1.0451-g sample was precipitated with an excess of paraperiodic acid, H5IO6:

2+ + 2H;IO, → Hgs(IO)2 + 10H* SH32* ->

The precipitate was filtered, washed free of precipitating agent, dried, and weighed, and 0.5718 g was recovered. Calculate the percentage of Hg2Cl2 in the sample.

2+ + 2H;IO, Hgs(IO)2 + 10H* SH32* ->

Step by Step Solution

3.40 Rating (153 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

1 mol Hg IO 5 mol Hg X 05718 ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

927-E-C-E-C-P (736).docx

120 KBs Word File

Students Have Also Explored These Related Chemical Engineering Questions!