Question: The number e can be defined Where n! = n(n1) 2 1 for n 0 and 0! = 1. Compute
Where n! = n(nˆ’1) · · · 2 · 1 for n ‰ 0 and 0! = 1. Compute the absolute error and relative error in the following approximations of e:
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n!
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