The time (in hours) that a technician requires to perform preventive maintenance on an air-conditioning unit is

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The time (in hours) that a technician requires to perform preventive maintenance on an air-conditioning unit is very different from unit to unit. Some problems take hours to fix, some can be done in minutes. Probability says that individual 'time' is governed by an exponential distribution, the precise nature of which is not an issue in Math 1530, except that we can use the mean time? = 1 hour and the standard deviation? = 1 hour from that individual-units distribution. Your company has a contract to maintain 70 of these units in an apartment building. While you do not know exactly how much time each unit will take, you must schedule technicians' time for a visit to this building based on the average time x? for the 70 units. Is it safe to budget an average of 1.1 hours per unit? Or should you budget an average of 1.25 hours? We believe that the manufacturing and distribution process associated with this type of air-conditioning unit is such that variation from one unit to the next is random. Thus, we treat these 70 air conditioners as an SRS from all units of this type. The central limit theorem says that the sample mean time x? spent working on 70 units has approximately the Normal distribution with mean equal to the population mean ? = 1 hour and standard deviation ?/?70 ? 0.12 hour. The 'sampling distribution' of x? is therefore approximately N(1, 0.12).
1.) Which graph represents the sampling distribution of x?
Accounts Payable 75,000 75,000 Factory Overhead Factory Overhead 32,000 Accounts Payable 32,000 Work in Process 75,000 W

2.) What is the probability that the average time exceeds 1.25 hours?
3.) A new contractor in a different city works with a complex that includes 100 of these air conditioning units. We can still treat these 100 air conditioners as an SRS(size n = 100) from all units of this type. The central limit theorem says that the sample mean time x? spent working on 100 units has approximately the Normal distribution with mean equal to the population mean ? = 1 hour and standard deviation ?/?n ?
4.) Use this new distribution to find the probability that the average maintenance time for 100 units x? is less than 0.88 hours.
5.) Use this new distribution to find the probability that the average maintenance time for 100 units x? is greater than 1.1 hours.

Distribution
The word "distribution" has several meanings in the financial world, most of them pertaining to the payment of assets from a fund, account, or individual security to an investor or beneficiary. Retirement account distributions are among the most...
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