Question: Use the answers obtained in Exercise 4 as initial approximations to Newton's method. Iterate until ||x(k) x(k1)|| In exercise a. b. c. d. 3X1-cos(X2X3)--= 0
a.
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b.
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c.
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d.
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3X1-cos(X2X3)--= 0 46-625E + 2x2-1 = 0. 10m-3 4 0 xi +x2-37 = 0, X1+X2 +X3-3=0. 15x1 + xi-4x3 = 13. xi + 10x2-x3 = 11. d-25x3 =-22. and 0 < XI < 2,0 x2-2-21s0 8x2x3 + 4 = 0.
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Newtons method gives the following a x 12 049999... View full answer
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