Use the SOR method with = 1.2 to solve the linear systems in Exercise 1 with a tolerance TOL = 103 in the l

Use the SOR method with ω = 1.2 to solve the linear systems in Exercise 1 with a tolerance
TOL = 10−3 in the l∞ norm.
In Exercise 1
a. 3x1 − x2 + x3 = 1,
3x1 + 6x2 + 2x3 = 0,
3x1 + 3x2 + 7x3 = 4.
b. 10x1 − x2 = 9,
−x1 + 10x2 − 2x3 = 7,
− 2x2 + 10x3 = 6.
c. 10x1 + 5x2 = 6,
5x1 + 10x2 − 4x3 = 25,
− 4x2 + 8x3 − x4 = −11,
− x3 + 5x4 = −11.
d. 4x1 + x2 + x3 + x5 = 6,
−x1 − 3x2 + x3 + x4 = 6,
2x1 + x2 + 5x3 − x4 − x5 = 6,
−x1 − x2 − x3 + 4x4 = 6,
2x2 − x3 + x4 + 4x5 = 6